Calculating the pressure (pa) in a room 2 Years, 1 Month ago
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Hello, i was wondering if someone here could answer my question;
If I have a single room, and have measured the following details;
Room Volume (m3) Air Supplied to the room (m3/h) Air exhaust from the room (m3/h) Air leakage/egress from the room (assuming there is a greater amount of supply than exhaust (m3/h))
Is there a calculation or formula that will allow me to calculate the pressure (pa) that will be in the room at the time that these measurements were taken, i.e. using the figures recorded?
If not then can I calculate the pressure (pa) in the room if I have any other, additional readings? If so what additional data do I need to allow me to calculate the pressure (pa) in my room?
Re:Calculating the pressure (pa) in a room 2 Years ago
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Ultimately the pressure in the room will be the same as the supply pressure, assuming what's leaking out is lower than what's going in.
How long it takes to get to that pressure is determined by the difference between entering and leaving. To get the pressure at any one time, use the magnahelic you got the other readings with, stick the low pressure tube under the door to outside the room, and read the dial.